Hence, the speed of the object on reaching the ground is 10 m/s. From second equation of motion, we have If the mass of A is MA, what must be the mass of B so that the value of g on B is half that of its value on A? Thus, Hence, from (i) and (ii), we observe that the time taken by the stone to go up is same as the time taken by it to come down. S=ut+12gt2⇒h=0+12×10×12⇒h=5 m Let u be the initial velocity of the object. The weight of a body depends on the local acceleration due to gravity where it is placed. Question from very important topics are covered by NCERT Exemplar Class 11.You also get idea about the type of questions and method to answer in your Class 11th … that can be asked in the final exam. GK Questions and Answers on Gravitation. For planet A: gA=GMArA2 Gravitation quiz questions and answers pdf, objects scintists sent to space and they revolves around earth are termed as, to practice for physics certifications. Balbharati solutions for Science and Technology Part 1 10th Standard SSC Maharashtra State Board chapter 1 (Gravitation) include all questions with solution and detail explanation. The chapter will focus on new terms and definitions related to gravitation. Weight is the force exerted on a body due to the gravitational pull of another body such as Earth, the sun and the moon. Answer the following : (a) Among the known types of forces in nature, the gravitational force is the weakest. Let the period of revolution of a planet at a distance R from a star be T. Prove that if it was at a distance of 2R from the star, its period of revolution will be 8 T. From Kepler's third law of planetary motion, we have (a) Gravitational Force (b) Electrostatic Force (c) Magnetic Force (d) None. A stone is thrown vertically upwards with initial velocity u reaches a height ‘h’ before coming down. Since the mass m of a planet is constant, equation (i) can be written as: a = -g Let h be the height of the table. Online test of Chapter 10 Gravitation 3 Science| Class 9th. g = 10 m/s2 (b) weight. S = 500 m Concepts covered in Science and Technology Part 1 10th Standard SSC Maharashtra State Board chapter 1 Gravitation are Concept of Gravitation, Circular Motion, Centripetal Force, Kepler’S Laws, Newton’s Universal Law of Gravitation, Earth’s Gravitational Acceleration, Variation in Value of g, Free Fall, Escape velocity, Concept of Weight, Gravitational Potential Energy. b. How long will the object take to come back to the earth? Weight is an extrinsic property of a body. Thus, using second equation of motion, we have d. A stone thrown vertically upwards with initial velocity u reaches a height ‘h’ before coming down. What will be their values on the moon? Answer: The atmosphere of earth is possible due to this law. Hence, the gravitational force between the sun and a planet is inversely proportional to the square of the distance between them. QUESTION 1 (1995 EXAM) (a) State Newton’s Universal Law of Gravitation in words (3 marks) (b) A satellite of mass (m) moves in orbit of a planet with mass (M). The mass of an object is the measure of its (a) pressure. u = u Take the Quiz and improve your overall Physics. Study the entries in the following table and rewrite them putting the connected items in a single row. Based on CBSE and NCERt guidelines. Chapter 13 - Why do We Fall ill. Chapter 14 - Natural Resources. Answer The universal law of gravitation states that every object in the universe attracts every other object with a force called the gravitational force.The force acting between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. Science_part_ _i_(solutions) Solutions for Class 10 Science Chapter 1 Gravitation are provided here with simple step-by-step explanations. Study the entries in the following table and rewrite them putting the connected items in a single row. Download PDF of NCERT Exemplar for Class 9 Science Chapter 10 – Gravitation . This force provides the necessary centripetal force to the planet to move in a … The distance between them is 3.8 × 105 km. Thus, the gravitational force at the centre on any body will be 0. The weight of a body can be measured using a spring balance and a weighing machine. A ball falls off a table and reaches the ground in 1 s. Assuming g = 10 m/s2, calculate its speed on reaching the ground and the height of the table. Class 9 Science Chapter 10 Extra Questions and Answers Gravitation. An object takes 5 s to reach the ground from a height of 5 m on a planet. (d) thrust. The acceleration due to gravity of a planet is given as Why? Thus, because of doubling of the pull on the object due to the floor, it will become two times more difficult to pull it along the floor. Pages. Gravitation Class 9 Extra Questions Very Short Answer Type. Use G = 6.7 × 10–11 N m2 kg–2 t = 5 s Here, u = 0 ⇒v = 10×1 = 10 m/s Chapter 10. W' = 2mg = 2W v = 0 T2∝r3 .....(i) Will the mass and weight of an object on the earth be same as their values on Mars? For planet B: gB=GMBrB2 1. g = 10 m/s2 Why? The questions involved in Balbharati Solutions are important questions The mass of an object is 60 kg on the earth. c. The mass and weight of an object on earth are 5 kg and 49 N respectively. Write the three laws given by Kepler. Shaalaa.com has the Maharashtra State Board Science and Technology Part 1 10th Standard SSC Maharashtra State Board solutions in a manner that help students grasp basic concepts better and faster. Both the bodies fall with the same acceleration towards the surface of the earth. S = h b. Gravitation Objective GK Questions and Answers. Download free CBSE Sample paper for Class 9, Physics. Name the force which is responsible for the revolution of planets around the sun. TopperLearning’s Experts and Students has answered all of Gravitation of MAHARASHTRA Class 10 Physics questions in detail. The distance between them is 3.8 × 105 km. Assume that the acceleration due to gravity on the moon is 1/6th of that on the earth. NCERT Solutions for Class 9 Science Chapter 10 – Gravitation – Intext Questions – Page No. Let the period of revolution of a planet at a distance R from a star be T. Prove that if it was at a distance of 2R from the star, its period of revolution will be \[\sqrt{8}\] T. An object takes 5 s to reach the ground from a height of 5 m on a planet. -2gh=v2-u2⇒u=2ghNow, from first equation of motion, we havev=u-gtt=ug=2hg .....(i) All questions and answers from the Science_part_ _i_(solutions) Book of Class 10 Science Chapter 1 are provided here for you for free. 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Solution: The universal law of gravitation states that every object in the universe attracts every other object with a force called the gravitational force. Using all the given values, we have Free PDF download of Important Questions with solutions for CBSE Class 9 Science Chapter 10 - Gravitation prepared by expert Science teachers from latest edition of CBSE(NCERT) books. Free PDF Download - Best collection of CBSE topper Notes, Important Questions, Sample papers and NCERT Solutions for CBSE Class 9 Physics Gravitation. Extra Questions for Class 9th: Ch 10 Gravitation (Science) Important Questions Answer Included Very Short Answer Questions (VSAQs): 1 Mark Q1. State the universal law of gravitation. ⇒MB=MArB22(12rB)2=2MA Why then does it play a dominant role for motion of bodies on the terrestrial, astronomical and cosmological scale? 3. (d) 100 N. 3. What is the centripetal force that makes moon revolve around earth? For vertical downward motion of the object, … Thus, from second equation of motion, we have b.The radius of planet A is half the radius of planet B. The radius of planet A is half the radius of planet B. Questin 2. These solutions for Gravitation are extremely popular among Class 10 students for Science Gravitation Solutions come handy for quickly completing your homework and preparing for exams. If not, what is the origin of these forces? What will be their values on the moon? T2∝R3 .....(ii) From third equation of motion, we have F=(6.7×10-11)(6×1024)(7.4×1022)(3.8×105×1000)2=20.6×1019≃2×1020 N What is the value of g on the planet? NCERT Solutions for Class 9 Science Chapter 10 - Gravitation [FREE]. Assume g = 10 m/s2 u = 0 Assume g = 10 m/s2. MCQ on gravitation.> In this post I come up with some important general knowledge questions with answers on a very crucial topic called Gravitation.These multiple choice questions are very important for upcoming exams for general science like SSC, CGL, CHSL, MTS, Railway Group-D, Group-C, IAS, UPSC Air force and Navy. Therefore, when F = 0, g has to be 0. Since, from Newton's law, we know 2gh=v'2⇒v'=2ghNow, from first equation of motion, we havev'=u+gt't'=v'g=2hg .....(ii) Using all the given values, we have Hence, the value of g on the planet is 0.4 m/s2. v2 ∝ r2/ T2...(v) F=GMeMsR2 Dec 09, 2020 - Short Long Answer Questions- Gravitation Class 9 Notes | EduRev is made by best teachers of Class 9. g=GMr2 g. The mass of the earth is 6 × 1024 kg. Newton used this formula to determine the force acting on a planet revolving around the Sun. Show that the time taken to go up is the same as the time taken to come down. e. If the value of g suddenly becomes twice its value, it will become two times more difficult to pull a heavy object along the floor. If the mass of A is MA, what must be the mass of B so that the value of g on B is half that of its value on A? He assumed that the orbits of the planets around the Sun are circular, and not elliptical, and so derived the inverse-square rule for gravitational force using the formula for centripetal force. Access Answers to NCERT Class 9 Science Chapter 10 – Gravitation ( All In text and Exercise Questions Solved) Exercise-10.1 Page: 134. f. The masses of the earth and moon are 6 × 1024 kg and 7.4 × 1022 kg, respectively. What is the difference between mass and weight of an object. Mass is the amount of matter contained in a body. or, v ∝ r/ T ...(iv) [as the factor 2π is a constant] What is the value of g on the planet? WM=16WE⇒WM=496=8.17 N W = mg Download free printable assignments worksheets of English from CBSE NCERT KVS schools, free pdf of CBSE Class 10 English Grammar Questions chapter wise important exam questions and answers CBSE Class 10 English Grammar Questions . a. Chapter 15 - Improvement in Food Resources. According to Kepler’s third law of planetary motion, the factor r3/ T2 is a constant. State the universal law of gravitation. Gravitational potential energy is given by the expression, W = m g h. where, h = Height above the ground = 10 m. m = Mass of the object = 50 kg. The distance between the earth and the sun is 1.5 × 1011 m. If the gravitational force between the two is 3.5 × 1022 N, what is the mass of the sun? Let v' be the velocity of the ball with which it hits the ground. (b) Do the forces of friction and other contact forces arise due to gravitational attraction? Show that the time taken to go up is same as the time taken to come down. Answer the following questions. Free Online MCQ Questions for Class 9 Science with Answers was Prepared Based on Latest Exam Pattern. The detailed, step-by-step solutions will help you understand the concepts better and clear your confusions, if any. Use G = 6.7 × 10–11 N m2 kg–2, a. CBSE Class 9 Science Important MCQs from Chapter 10 Gravitation for Annual Exam 2020 Check MCQs on Class 9 Science Chapter 10 - Gravitation. Dividing (iii) by (ii), we get The students should read these basic concepts to gain perfection which will help him to get more marks in CBSE Answer: The acceleration due to gravity does not depend upon the mass of the stone or body. v = 2πr/ T ...(iii) where, r is the radius of the circular orbit of the planet How long will the object take to come back to the earth? S = 500 m The distance between the earth and the sun is 1.5 × 1011 m. If the gravitational force between the two is 3.5 × 1022 N, what us the mass of the sun? Let v be the velocity of the ball on reaching the ground. F = mg Now, let t1 be time taken by the object to reach at 500 m height. Gravity is also known as gravitation which is a force of attraction that acts between all the matter. This document is highly rated by Class 9 students and has been viewed 414 times. S=ut +12gt25 =12g(5)2g=1025=0.4 m/s2 e. Let the mass of the heavy object be m. Thus, the weight of the object or the pull of the floor on the object is e. Here, t =1 s Answer: The weighing machine actually measures the weight of the body as the acceleration due to gravity ‘g’ is acting on the body. a. On using equation (vii) in equation (ii), we get: Weight of the object on Earth, WE = 49 N They have 15 multiple choice questions, 7 short answer questions and 4 long answer questions. Now, if the planet takes time T to complete one revolution around the Sun, then its velocity v is given as: g = Acceleration due to gravity = 10 ms-2. Chapter 11 - Work and Energy. Balbharati textbook solutions can be a core help for self-study and acts as a perfect self-help guidance for students. The entire NCERT textbook questions have been solved by best teachers for you. u = 0 For vertical downward motion of the stone: F=GMeMmR2 Gravitation multiple choice questions (MCQs), gravitation quiz answers pdf 10, learn physics online courses. Questions : 1. Difference between mass and weight of an object is as follows: Newton used Kepler’s third law of planetary motion to arrive at the inverse-square rule. Since weight is a force, its SI unit is newton (N). How did they help Newton to arrive at the inverse square law of gravity? v2 ∝ 1/ r...(vii) Explain why the value of g is zero at the centre of the earth. a. This will clear students doubts about any question and improve application skills while preparing for board exams. F∝1r2 Chapter 12 - Sound. (d) 9.8 m/s 2 Question 2. Chapter 10 - Gravitation. This is given as: As mass is the quantity of inertia, it remains the same. Extra Questions for Class 9 Science Chapter 10 Gravitation with Answers Solutions . In the similar manner, force due to any portion of the Earth at the centre will be cancelled due to the portion opposite to it. v=u+at⇒0=100-10×t1t1=10 s where, Me and Ms are the masses of the Earth and the Sun, respectively. You will also love the ad-free experience on Meritnation’s Science_part_ _i_(solutions) Solutions. 1. On squaring both sides of this equation, we get: NCERT Solutions Class 9 Science Chapter 10 Gravitation answers of intext questions given on Page 134 or Page 136 or Page 138 or Page 141 or Page 142 or Exercises in English Medium updated for new academic session 2020-21. Given: rA=12rB What are (i) free fall, (ii) acceleration due to gravity (iii) escape velocity (iv) centripetal force ? Free Online MCQ Questions for Class 9 Science Chapter 10 – Gravitation with Answers. (d) 360 kg. Calculate the gravitational force of attraction between the two? The Following Section consists of Gravitation Questions on Physics. S=ut+12at2⇒500=102×t22⇒t2=10 s The mass and weight of an object on earth are 5 kg and 49 N respectively. After you have studied lesson, you must be looking for answers of its questions. Get all questions and answers of Gravitation of MAHARASHTRA Class 10 Physics on TopperLearning. 3.5×1022=(6.7×10-11)(6×1024)×Ms(1.5×1011)2⇒Ms=(3.5×1022)×(1.5×1011)2(6.7×10-11)×(6×1024)=1.96×1030 kg, View NCERT Solutions for all chapters of Class 10, FREE Downloadable NCERT Solutions.Works without internet, TS Grewal Solutions for Class 12 Commerce, TS Grewal Solutions for Class 11 Commerce, Homework Questions for Class 11 Humanities, Homework Questions for Class 12 Humanities, CBSE Class 10 Board Paper Solutions for Math, CBSE Class 10 Board Paper Solutions for Science, CBSE Class 10 Board Paper Solutions for Social Science, CBSE Class 10 Board Paper Solutions for English, CBSE Class 10 Board Paper Solutions for Hindi, CBSE Class 12 Science Board Paper Solutions for Math, CBSE Class 12 Science Board Paper Solutions for Physics, CBSE Class 12 Science Board Paper Solutions for Chemistry, CBSE Class 12 Science Board Paper Solutions for Biology, CBSE Class 12 Commerce Board Paper Solutions for Economics, CBSE Class 12 Commerce Board Paper Solutions for Accountancy, CBSE Class 12 Commerce Board Paper Solutions for Business Studies, CBSE Class 12 Commerce Board Paper Solutions for Math, CBSE Class 12 Humanities Board Paper Solutions for English. T12∝(2R)3orT12∝8R3 .....(iii) What is the difference between mass and weight of an object? (b) 60 kg. At the centre of Earth, the force due to upper half of the Earth will cancel the force due to lower half. a = g MCQ Questions for Class 9 Science Chapter 10 Gravitation with Answers MCQs from Class 9 Science Chapter 10 – Gravitation are provided here to help students prepare for their upcoming Science exam. Since, mass m of an object can never be 0. W = 50 × 10 × 10 = 5000 J. gB=12gA (Given)or, GMBrB2=GMA2rA2⇒MB=MArB22rA2 These solutions for Gravitation are extremely popular among Class 10 students for Science Gravitation Solutions come handy for quickly completing your homework and preparing for exams. d. An object thrown vertically upwards reaches a height of 500 m. What was its initial velocity? Answer. Will the mass and weight of an object on the earth be same as their values on Mars? f. The gravitational force between the Moon and the Earth can be found out using the formula, The mass of moon is about 0.012 times that of the earth and its […] State one phenomena related to universal law of gravitation. g = -10 m/s2 Balbharati solutions for Science and Technology Part 1 10th Standard SSC Maharashtra State Board chapter 1 (Gravitation) include all questions with solution and detail explanation. Now, Question 10. A collection of questions on CBSE-Gravitation with solutions created by best teachers are available as a PDF download. v2-u2=2aS⇒0-u2=-2×10×500⇒u=100 m/s These important questions are provided with answers. (CBSE 2015) Answer: The gravitational force of attraction between the planet and the sun. where, Me and Mm are the masses of the Earth and the Moon, respectively. d. For vertical upward motion of the stone: On multiplying and dividing the right-hand side of this relation by r, we get: v2∝r3T2×1r ...(vi) Mass of the object on Moon = 5 kg (since mass is independent of the place of observation) Explain why the value of g is zero at the centre of the earth. Further, we at Shaalaa.com provide such solutions so that students can prepare for written exams. 2. Use G = 6.7 × 10–11 N m2 kg–2. Let t be the time taken by the ball to reach height h. Thus, using second equation of motion, we have This will clear students doubts about any question and improve application skills while preparing for board exams. Home; Resources; Class 12; Class 11; Class … Question 1. Page No: 134. S = h Now, when the distance of the planet from the star is 2R, then its period of revolution becomes g. The gravitational force between the Sun and the Earth can be found out using the formula, MCQs from CBSE Class 9 Science Chapter 10: Gravitation 1. Register online for Science tuition on Vedantu.com to score more marks in your examination. The weight of a 1 kilogram mass body on the earth will be (a) 1 N. (b) 9.8 N. (c) 0. Thus, the mass of planet B should be twice that of planet A. The mass of a body can be measured using a beam balance and a pan balance. This solution contains questions, answers, images, explanations of the complete Chapter 10 titled The Fun They Had of Maths taught in class 9. NCERT Exemplar Class 11 Physics is very important resource for students preparing for XI Board Examination. All questions and answers from the Science_part_ _i_(solutions) Book of Class 10 Science Chapter 1 are provided here for you for free. The value of acceleration due to gravity on the surface of the earth at sea level is (a) 4.9 m/s 2 (b) 6 m/s 2 (c) 8 m/s 2 (d) 9.8 m/s 2 Answer. From second equation of motion, we have Why? 134. 1. Thus, the value of g is zero at the centre of Earth. u = 0 At half-way down, the potential energy of the object will be, T12T2=8R3 R3⇒T1=8T, Solve the following examples. Here we have provided NCERT Exemplar Problems Solutions along with NCERT Exemplar Problems Class 11.. Let t' be the time taken by the ball to reach the ground. If you are a student of class 9 who is using NCERT Textbook to study Maths, then you must come across Chapter 10 Gravitation. d. For vertical upward motion of the object, S = 5 m F ∝ v2/ r ...(ii) e. A ball falls off a table and reaches the ground in 1 s. Assuming g = 10 m/s2, calculate its speed on reaching the ground and the height of the table. Thus, the total time taken by the object to reach back to Earth = t1 + t2 = 20 s If the value of g suddenly becomes twice its value, it will become two times more difficult to pull a heavy object along the floor. Thus, from first equation of motion, we have This object was carried to the moon. The mass of a body remains the same everywhere in the universe. An object thrown vertically upwards reaches a height of 500 m. What was its initial velocity? Hence the mass reading of 42 kg given by a weighing machine is same as the actual mass of the body. Now, if g becomes twice, the weight of the object or the pull of the floor on the object also becomes twice i.e. How did they help Newton to arrive at the inverse square law of gravity? Gravitation | Physics | MCQ - Multiple Choice Questions | CBSE Class 9th Question 1. Question 11. c. Mass of the object on Earth, m = 5 kg (c) 10 kg. Visit the below link to get free NCERT Exemplar for Class 9 Science Chapter 9. Body remains the same acceleration towards the surface of the earth have lesson... Solved ) Exercise-10.1 Page: 134 09, 2020 - Short long answer questions and Answers.. Answers Gravitation used this formula to determine the force acting on a planet revolving around the sun and cosmological?... 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